Operator precedence in java
Operator precedence is the order in which operators are evaluated in an expression. Operators with higher precedence are evaluated before operators with lower precedence.
The following table shows the operator precedence in Java:
| Operator |
Precedence |
| () [] . ? : |
Highest |
| ++ -- ! ~ * / % + - |
Unary |
| * / % |
Multiplication and division |
| + - |
Addition and subtraction |
| < > <= >= instanceof |
Comparison |
| == != |
Equality |
| & |
Bitwise AND |
| ` |
Bitwise XOR |
| && |
Logical AND |
| ? |
Ternary |
The order of evaluation can be changed by using parentheses. Parentheses have the highest precedence, so the expressions inside parentheses are evaluated first.
Here is an example of how operator precedence works:
int x = 10;
int y = 20;
int z = x + y * 2;
In this expression, the multiplication is evaluated first, followed by the addition. So, the value of z will be 30.
If we want to change the order of evaluation, we can use parentheses. For example:
int z = (x + y) * 2;
In this expression, the addition is evaluated first, followed by the multiplication. So, the value of z will be 50.
Operator precedence is an important concept to understand in Java. It can help you to write clear and concise code that is easy to understand and debug.
Here are some additional details about operator precedence in Java:
Operators with the same precedence are evaluated from left to right.
The parentheses can be used to override the default operator precedence.
The operator precedence can be changed by using the
instanceof operator.
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